How to hide action buttons(being used as hyperlink) for different condition in xCP 2.0

shashank329

I have added a menu on master page where two items A and B are there. Both A and B are linked to a single page.

On that page I have a resultlist having two action buttons in two columns of resultlist behaving as hyperlink.

I want to hide these buttons on the basis of following conditions:

Hide Button 1: If I select option A from menu items

Hide Button 2 : If select option B from menu items

Plz guide me how to do it.

Thanks

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elboukhari

Hi shashank329 ,

using XCP 2.0 i can't see any option you having but duplicating your page and link each one of them to related menu Item.

i suppose even in 2.1 where session variable are available you can't bind that in menu Item so no solution for that too.

a more challanging way is to customize the menu item widget so on click it add a variable to XCP data object or EXTJs Contexts so you may use it in pages using javaScript function to hide and display but i would not recommand that since it is costing more than duplicating pages and adding hard coded logic to you application.

hope this helps

Otman

shashank329

Thanks Otman

This is what I found after exploring all the options availble in xCP 2.0

plz explain the other option u suggested, i would like to explore this for any future reference.

elboukhari

Hi ,

a quick tought :

you can create an override of the xcp_nav_button widget to update the onClick method ( of course check if the onClick in the method called for your actions )

and then push the value of the text of your menu to a global variable that you can grab from every page.

this way you know what menu was clicked.

i wont recommand this since it is cause issue with your code that will be coupled to your label and still the management of refresh of the pages can be tricky

Otman