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Variable Substitution Question

ReggieRWalker

ENV: TS 6.5 sp3 | Win Server 2K3 Ent.

This *should* work...so I need another pair of eyes please:
------------------------------------------------------------------
# Get Passed In Variables
my $wf_template = $ARGV[0];
my $filename = $ARGV[1];
my $workarea = $ARGV[2];

$filename =~ s|$workarea||;
------------------------------------------------------------------

If $filename = /this/is/the/dir/name and $workarea = /this/is/the/dir, then I would think that this:

$filename =~ s|$workarea||;

would result in /name. Or am I totally whacked?

TIA

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Comments

nipper

try =~ s|\Q$workarea||;

nipper

Also, you will be getting the workarea-relative path, not the specific filename.
so if the path was /d/m/foo/WA/mine/some/dirs/bar.html
and you are passed /d/m/foo/WA/mine/ then you are left with some/dirs/bar.html

just an FYI,

ReggieRWalker

Thanks Nipper. That worked perfectly.