Need shell script to extract branch name

Hi,

I need some help in shell script, i tried with perl script and it is working but unfortunately with Shell scripts it is not working for me.

Requirement:

I have the variable path assign to these values.

path="/default/main/Modular_Site/Maintenance/master/WORKAREA/kelm"
path="/default/main/Modular_Site/LiveSite/market/WORKAREA/ejmk"
path="/default/main/Modular_Site/NrSite/market/WORKAREA/fjlm"

From path I need to extract Maintenance / LiveSite / NrSite and assign to a variable.

Any idea ?

##### or

In perl this regex will extract it $branch =~ s/.*\/(.*)\/.*\/WORKAREA\/.*/$1/;
But how using shell script, thats my question,

######
\
could you please help me out here,

Warm Regards
Lal

IW 6.7.1
Redhat Linux

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Comments

nipper

which shell ? (/bin/sh, bash, etc)

Why can't you use perl ?

You can use awk/sed for that, but those are a *serious* pain (I have not done any awk/sed for for 10 years)

Lal

Hi,

I need it in bash.

I saw some scripts here using sed but I am not getting my result.

http://www.linuxquestions.org/questions/programming-9/shell-script-string-parsing-362534/

Warm Regards
LAL

nipper

well the, good luck. sed is the right tool to use but it is a serious pain.

Several years ago I could have written it easily, not now. Maybe jed will chime in. Otherwise keep playing with it.

Lal

After some trial and error I got a solution.

#!/bin/sh
################## Modified include.sh ##############

var1="/default/main/Modular_Site/"
var2="/master/STAGING/$1"

path=$IW_WORKAREA
path="/default/main/MSite/LiSite/master/WORKAREA/ejlmkr"
branch=`echo $path | perl -wlne 'print $1 if /.*\/(.*)\/.*\/WORKAREA\/.*/'`
fpath="${var1}${branch}${var2}"
/bin/cat $fpath
exit 0

ISCBorisB

...i tried with perl [...] it is working

Since you ended up using Perl anyway why would you need shell scripting?

nipper

Since you ended up using Perl anyway why would you need shell scripting?

I can only assume that he needed to incorporate this into an already existing script.

Migrateduser

People still use awk and sed? Those sounds so ancient. You can easily accomplish that with perl one liner.