nav[aria-label="Primary Navigation"] { padding: 0; & ul { list-style: none; width: 100%; display: flex; flex-direction: row; justify-content: start; align-items: start; gap: 30px; padding: 0; & li { margin: 0; } & ul li { list-style: none; } } }

Merge DCRs in 2 branches

tsatt

Hi,

I am working on a perl script to merge 2 DCRs in 2 different branches.
I am using DCRnode module and am having issues setting specific nodes in the XML.

Using some logic I have an array of nodes that contains final nodes that need to be in the tree. I want to for example in section ID A replace Links A1 and Links A2 with the new list that contains 3 links and same for section ID B. I wish there was a replaceNode function or something in DCRnode.

ok the structure fo the DCR is like this
<record>
  <sections>
      <Id>A</Id>
      <Links>
         <Id>A1</Id>
      </Links>
      <Links>
         <Id>A2</Id>
      </Links>
  </sections>
  <sections>
      <Id>B</Id>
      <Links>
         <Id>B1</Id>
      </Links>
      <Links>
         <Id>B2</Id>
      </Links>
  </sections>
</record>

Thanks

Solaris 8
TeamSite 6.5

Find more posts tagged with

Comments

nipper

Is that example the final output or one of the source DCRs ? Post both the source and output and what you are currently using andy someone may be able to help.

FWIW, when I have this type of issue, I never update with DCRNode. Rather I read one or both files in and parse them with one of the stock parsers. Then I build XML by hand instead of using a PM to build it.

For easy merges one can also use regex.

For my money those are easier and faster.

HTH

Andy

tsatt

Thanks for replying.

The example in the original post was of the source DCR.
The target DCR will basically have more Link nodes in each sections.
Example snippet below: LInks within Section with ID A will have 4 links instead of 2.

<Links>
<Id>A1</Id>
</Links>
<Links>
<Id>A2</Id>
</Links>
<Links>
<Id>A3</Id>
</Links>
<Links>
<Id>A4</Id>
</Links>

Tying to do something like, get all the nodes of Links and replace with my new node list of links in each section

Thanks

tsatt

I found the solution.

I was initially trying to use set_node_list but was having issue as it would replace everything with the new nodes which I did not want as I only wanted to replace nodes of specific kind. So I used set_inner_xml method along with regex search and replace. One thing I was doing wrong was of using get_xml instead of get_inner_xml method to get the xml of the parent node and therefore was getting Links within Links nodes.

It is working now.

Thanks

GridCells.rptdesign