Link for getting a report from server

Hi All,

I have a java application integrated with the birt engine API running on a tomcat server. I'm still testing out stuff. What I want to know is after i've created a report and stored it in a directory within a folder in the webapp, how do I generate a link to the report to be accessable to different clients?

thanks in advance
Yusuf

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JasonW

Yusuf,

Can you give some more detail?
In your servlet you can always open the report designs like:
design = birtReportEngine.openReportDesign( yourServletContext.getRealPath("/Reports")+"/"+reportName );

The /Reports directory would be in your webapp.

Jason

yusufnazir

Hi Jason,

Thanks for the reply.

I solved the problem.
I am working with spring mvc en i was getting and error when i called getOutputStream() method because i was returning a view within my controller class.

Here's the controller class that works:
public class PDFController extends AbstractController {

protected ModelAndView handleRequestInternal(HttpServletRequest req, HttpServletResponse resp) throws Exception {
ServletOutputStream out;
String reportName = req.getParameter("ReportName");
ServletContext context = req.getSession().getServletContext();
String sessionId = new String(req.getSession().getId());
String report = new String(reportName.concat(".pdf"));

resp.addHeader("Content-Disposition", "attachment; filename="" + "WEB-INF/tempReports/"+sessionId+"/"+report+ """);

byte[] buf = new byte[1024];

try{
String realPath = context.getRealPath("WEB-INF/tempReports/"+sessionId+"/"+report);
File file = new File(realPath);
long length = file.length();
BufferedInputStream in = new BufferedInputStream(new FileInputStream(file));
out = resp.getOutputStream();
resp.setContentLength((int)length);
while ((in != null) && ((length = in.read(buf)) != -1)) {
out.write(buf, 0, (int)length);
}
in.close();
out.close();
}catch (Exception exc){
exc.printStackTrace();
}
return null;
}

}

instead of returning null i was returning new ModelAndView("........")