dnrDeploymentJob and state=success problem

mamoudou

Hi all,

I am using OpenDeploy Version 5.6.0.0.0 Build 15978 and I have a problem with the sequence of execution:

--------------
<deployment name="MyDeployement" transactional="yes" >
<execDeploymentTask useDefinition="MyDefinition" />
<dnrDeploymentJob location="source" when="after" state="success">
<script cmd="/iw-home/OpenDeployNG/bin/iwodstart AnOtherDeploymentFile -k edition=$edition" />
</dnrDeploymentJob>
</deployment>
--------------

Even if the "MyDefinition" deployment fails, the script in the dnrDeploymentJob is executed, what should never hapen.
I put state="success", but in the logfile there is always:

-------------
(2) RunScripts when=client_after_all on state=always
(2) Executed script [/iw-home/OpenDeployNG/bin/iwodstart AnOtherDeploymentFile -k edition=STAGING] where [] as [root] succeeded
-------------

How could I have the correct behavior:
if deployment 1 fails, DO NOT run deployment 2?

Note: due to some particular reasons, I have to use dnr for the second deployment

Thanks for your help,
Mamoudou

fuzzy

Hi, this is a sample you have closed you executeDeploymentTask \> and should not look bellow
<execDeploymentTask useDefinition="Code_Deployment">
<deployNRun >
<dnrDeployment location="target"
when="before"
state="always" >
<script cmd="/....^"
as="root"
where="/tmp"
/>
</dnrDeployment>
</deployNRun>
</execDeploymentTask>


Farzam
ffarzanehfar@yahoo.co.uk"> ffarzanehfar@yahoo.co.uk